(4x-1)(4x+1)(x-4)=0

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Solution for (4x-1)(4x+1)(x-4)=0 equation: 


Simplifying
(4x + -1)(4x + 1)(x + -4) = 0

Reorder the terms:
(-1 + 4x)(4x + 1)(x + -4) = 0

Reorder the terms:
(-1 + 4x)(1 + 4x)(x + -4) = 0

Reorder the terms:
(-1 + 4x)(1 + 4x)(-4 + x) = 0

Multiply (-1 + 4x) * (1 + 4x)
(-1(1 + 4x) + 4x * (1 + 4x))(-4 + x) = 0
((1 * -1 + 4x * -1) + 4x * (1 + 4x))(-4 + x) = 0
((-1 + -4x) + 4x * (1 + 4x))(-4 + x) = 0
(-1 + -4x + (1 * 4x + 4x * 4x))(-4 + x) = 0
(-1 + -4x + (4x + 16x2))(-4 + x) = 0

Combine like terms: -4x + 4x = 0
(-1 + 0 + 16x2)(-4 + x) = 0
(-1 + 16x2)(-4 + x) = 0

Multiply (-1 + 16x2) * (-4 + x)
(-1(-4 + x) + 16x2 * (-4 + x)) = 0
((-4 * -1 + x * -1) + 16x2 * (-4 + x)) = 0
((4 + -1x) + 16x2 * (-4 + x)) = 0
(4 + -1x + (-4 * 16x2 + x * 16x2)) = 0
(4 + -1x + (-64x2 + 16x3)) = 0
(4 + -1x + -64x2 + 16x3) = 0

Solving
4 + -1x + -64x2 + 16x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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