(4x-1)(4x+1)=0

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Solution for (4x-1)(4x+1)=0 equation:


Simplifying
(4x + -1)(4x + 1) = 0

Reorder the terms:
(-1 + 4x)(4x + 1) = 0

Reorder the terms:
(-1 + 4x)(1 + 4x) = 0

Multiply (-1 + 4x) * (1 + 4x)
(-1(1 + 4x) + 4x * (1 + 4x)) = 0
((1 * -1 + 4x * -1) + 4x * (1 + 4x)) = 0
((-1 + -4x) + 4x * (1 + 4x)) = 0
(-1 + -4x + (1 * 4x + 4x * 4x)) = 0
(-1 + -4x + (4x + 16x2)) = 0

Combine like terms: -4x + 4x = 0
(-1 + 0 + 16x2) = 0
(-1 + 16x2) = 0

Solving
-1 + 16x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 16x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 16x2 = 0 + 1
16x2 = 0 + 1

Combine like terms: 0 + 1 = 1
16x2 = 1

Divide each side by '16'.
x2 = 0.0625

Simplifying
x2 = 0.0625

Take the square root of each side:
x = {-0.25, 0.25}

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