(4x-1)(4x+1)=8x(2x-1)

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Solution for (4x-1)(4x+1)=8x(2x-1) equation: 



(4x-1)(4x+1)=8x(2x-1)

We move all terms to the left:

(4x-1)(4x+1)-(8x(2x-1))=0

We use the square of the difference formula

16x^2-(8x(2x-1))-1=0



We calculate terms in parentheses: -(8x(2x-1)), so:

8x(2x-1)

We multiply parentheses

16x^2-8x

Back to the equation:

-(16x^2-8x)



We get rid of parentheses

16x^2-16x^2+8x-1=0

We add all the numbers together, and all the variables

8x-1=0

We move all terms containing x to the left, all other terms to the right

8x=1

x=1/8

x=1/8

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