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(4x-1)(5x+6)=0
We multiply parentheses ..
(+20x^2+24x-5x-6)=0
We get rid of parentheses
20x^2+24x-5x-6=0
We add all the numbers together, and all the variables
20x^2+19x-6=0
a = 20; b = 19; c = -6;
Δ = b2-4ac
Δ = 192-4·20·(-6)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-29}{2*20}=\frac{-48}{40} =-1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+29}{2*20}=\frac{10}{40} =1/4 $
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