(4x-1)+(3x+1)+(x+4)=12

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Solution for (4x-1)+(3x+1)+(x+4)=12 equation:


Simplifying
(4x + -1) + (3x + 1) + (x + 4) = 12

Reorder the terms:
(-1 + 4x) + (3x + 1) + (x + 4) = 12

Remove parenthesis around (-1 + 4x)
-1 + 4x + (3x + 1) + (x + 4) = 12

Reorder the terms:
-1 + 4x + (1 + 3x) + (x + 4) = 12

Remove parenthesis around (1 + 3x)
-1 + 4x + 1 + 3x + (x + 4) = 12

Reorder the terms:
-1 + 4x + 1 + 3x + (4 + x) = 12

Remove parenthesis around (4 + x)
-1 + 4x + 1 + 3x + 4 + x = 12

Reorder the terms:
-1 + 1 + 4 + 4x + 3x + x = 12

Combine like terms: -1 + 1 = 0
0 + 4 + 4x + 3x + x = 12
4 + 4x + 3x + x = 12

Combine like terms: 4x + 3x = 7x
4 + 7x + x = 12

Combine like terms: 7x + x = 8x
4 + 8x = 12

Solving
4 + 8x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 8x = 12 + -4

Combine like terms: 4 + -4 = 0
0 + 8x = 12 + -4
8x = 12 + -4

Combine like terms: 12 + -4 = 8
8x = 8

Divide each side by '8'.
x = 1

Simplifying
x = 1

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