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(4x-1)-(2x+1)=5x-(4x-1)
We move all terms to the left:
(4x-1)-(2x+1)-(5x-(4x-1))=0
We get rid of parentheses
4x-2x-(5x-(4x-1))-1-1=0
We calculate terms in parentheses: -(5x-(4x-1)), so:We add all the numbers together, and all the variables
5x-(4x-1)
We get rid of parentheses
5x-4x+1
We add all the numbers together, and all the variables
x+1
Back to the equation:
-(x+1)
2x-(x+1)-2=0
We get rid of parentheses
2x-x-1-2=0
We add all the numbers together, and all the variables
x-3=0
We move all terms containing x to the left, all other terms to the right
x=3
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