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(4x-1)-2(x+1)=3x(4x+2)
We move all terms to the left:
(4x-1)-2(x+1)-(3x(4x+2))=0
We multiply parentheses
(4x-1)-2x-(3x(4x+2))-2=0
We get rid of parentheses
4x-2x-(3x(4x+2))-1-2=0
We calculate terms in parentheses: -(3x(4x+2)), so:We add all the numbers together, and all the variables
3x(4x+2)
We multiply parentheses
12x^2+6x
Back to the equation:
-(12x^2+6x)
2x-(12x^2+6x)-3=0
We get rid of parentheses
-12x^2+2x-6x-3=0
We add all the numbers together, and all the variables
-12x^2-4x-3=0
a = -12; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·(-12)·(-3)
Δ = -128
Delta is less than zero, so there is no solution for the equation
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