(4x-1)-2(x+1)=3x(4x+2)

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Solution for (4x-1)-2(x+1)=3x(4x+2) equation: 



(4x-1)-2(x+1)=3x(4x+2)

We move all terms to the left:

(4x-1)-2(x+1)-(3x(4x+2))=0

We multiply parentheses

(4x-1)-2x-(3x(4x+2))-2=0

We get rid of parentheses

4x-2x-(3x(4x+2))-1-2=0



We calculate terms in parentheses: -(3x(4x+2)), so:

3x(4x+2)

We multiply parentheses

12x^2+6x

Back to the equation:

-(12x^2+6x)



We add all the numbers together, and all the variables

2x-(12x^2+6x)-3=0

We get rid of parentheses

-12x^2+2x-6x-3=0

We add all the numbers together, and all the variables

-12x^2-4x-3=0

a = -12; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·(-12)·(-3)
Δ = -128
Delta is less than zero, so there is no solution for the equation

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