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(4x-1)/3=x+2
We move all terms to the left:
(4x-1)/3-(x+2)=0
We get rid of parentheses
(4x-1)/3-x-2=0
We multiply all the terms by the denominator
(4x-1)-x*3-2*3=0
We add all the numbers together, and all the variables
(4x-1)-x*3-6=0
Wy multiply elements
(4x-1)-3x-6=0
We get rid of parentheses
4x-3x-1-6=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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