(4x-1)/5=(2-3x)/6

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Solution for (4x-1)/5=(2-3x)/6 equation: 



(4x-1)/5=(2-3x)/6

We move all terms to the left:

(4x-1)/5-((2-3x)/6)=0

We add all the numbers together, and all the variables

(4x-1)/5-((-3x+2)/6)=0

We calculate fractions


4x/()+(-((-3x+2)*5)/()=0



We calculate terms in parentheses: +(-((-3x+2)*5)/(), so:

-((-3x+2)*5)/(

We multiply all the terms by the denominator


-((-3x+2)*5)



We calculate terms in parentheses: -((-3x+2)*5), so:

(-3x+2)*5

We multiply parentheses

-15x+10

Back to the equation:

-(-15x+10)



We get rid of parentheses

15x-10

Back to the equation:

+(15x-10)



We get rid of parentheses

4x/()+15x-10=0

We multiply all the terms by the denominator


4x+15x*()-10*()=0

We add all the numbers together, and all the variables

4x+15x*()=0

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