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(4x-10)(5x+20)=0
We multiply parentheses ..
(+20x^2+80x-50x-200)=0
We get rid of parentheses
20x^2+80x-50x-200=0
We add all the numbers together, and all the variables
20x^2+30x-200=0
a = 20; b = 30; c = -200;
Δ = b2-4ac
Δ = 302-4·20·(-200)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-130}{2*20}=\frac{-160}{40} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+130}{2*20}=\frac{100}{40} =2+1/2 $
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