(4x-10)+(2x+52)=132

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Solution for (4x-10)+(2x+52)=132 equation: 



(4x-10)+(2x+52)=132

We move all terms to the left:

(4x-10)+(2x+52)-(132)=0

We get rid of parentheses

4x+2x-10+52-132=0

We add all the numbers together, and all the variables

6x-90=0

We move all terms containing x to the left, all other terms to the right

6x=90

x=90/6

x=15

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