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(4x-11)(4x+11)=0
We use the square of the difference formula
16x^2-121=0
a = 16; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·16·(-121)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*16}=\frac{-88}{32} =-2+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*16}=\frac{88}{32} =2+3/4 $
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