(4x-12)+(2x+42)+90=180

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Solution for (4x-12)+(2x+42)+90=180 equation: 



(4x-12)+(2x+42)+90=180

We move all terms to the left:

(4x-12)+(2x+42)+90-(180)=0

We add all the numbers together, and all the variables

(4x-12)+(2x+42)-90=0

We get rid of parentheses

4x+2x-12+42-90=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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