(4x-12)+(x+16)+(x+10)=180

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Solution for (4x-12)+(x+16)+(x+10)=180 equation: 



(4x-12)+(x+16)+(x+10)=180

We move all terms to the left:

(4x-12)+(x+16)+(x+10)-(180)=0

We get rid of parentheses

4x+x+x-12+16+10-180=0

We add all the numbers together, and all the variables

6x-166=0

We move all terms containing x to the left, all other terms to the right

6x=166

x=166/6

x=27+2/3

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