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(4x-12)=(2x+20)=90
We move all terms to the left:
(4x-12)-((2x+20))=0
We get rid of parentheses
4x-((2x+20))-12=0
We calculate terms in parentheses: -((2x+20)), so:We get rid of parentheses
(2x+20)
We get rid of parentheses
2x+20
Back to the equation:
-(2x+20)
4x-2x-20-12=0
We add all the numbers together, and all the variables
2x-32=0
We move all terms containing x to the left, all other terms to the right
2x=32
x=32/2
x=16
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