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(4x-13)=(3x+40)
We move all terms to the left:
(4x-13)-((3x+40))=0
We get rid of parentheses
4x-((3x+40))-13=0
We calculate terms in parentheses: -((3x+40)), so:We get rid of parentheses
(3x+40)
We get rid of parentheses
3x+40
Back to the equation:
-(3x+40)
4x-3x-40-13=0
We add all the numbers together, and all the variables
x-53=0
We move all terms containing x to the left, all other terms to the right
x=53
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