(4x-15)=(2x+35)

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Solution for (4x-15)=(2x+35) equation: 



(4x-15)=(2x+35)

We move all terms to the left:

(4x-15)-((2x+35))=0

We get rid of parentheses

4x-((2x+35))-15=0



We calculate terms in parentheses: -((2x+35)), so:

(2x+35)

We get rid of parentheses

2x+35

Back to the equation:

-(2x+35)



We get rid of parentheses

4x-2x-35-15=0

We add all the numbers together, and all the variables

2x-50=0

We move all terms containing x to the left, all other terms to the right

2x=50

x=50/2

x=25

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