(4x-16)+(3x-6)=27

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Solution for (4x-16)+(3x-6)=27 equation: 



(4x-16)+(3x-6)=27

We move all terms to the left:

(4x-16)+(3x-6)-(27)=0

We get rid of parentheses

4x+3x-16-6-27=0

We add all the numbers together, and all the variables

7x-49=0

We move all terms containing x to the left, all other terms to the right

7x=49

x=49/7

x=7

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