(4x-16)+6x=(11x-31)

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Solution for (4x-16)+6x=(11x-31) equation:



(4x-16)+6x=(11x-31)
We move all terms to the left:
(4x-16)+6x-((11x-31))=0
We add all the numbers together, and all the variables
6x+(4x-16)-((11x-31))=0
We get rid of parentheses
6x+4x-((11x-31))-16=0
We calculate terms in parentheses: -((11x-31)), so:
(11x-31)
We get rid of parentheses
11x-31
Back to the equation:
-(11x-31)
We add all the numbers together, and all the variables
10x-(11x-31)-16=0
We get rid of parentheses
10x-11x+31-16=0
We add all the numbers together, and all the variables
-1x+15=0
We move all terms containing x to the left, all other terms to the right
-x=-15
x=-15/-1
x=+15

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