(4x-16)+6x=(11x-31)

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Solution for (4x-16)+6x=(11x-31) equation: 



(4x-16)+6x=(11x-31)

We move all terms to the left:

(4x-16)+6x-((11x-31))=0

We add all the numbers together, and all the variables

6x+(4x-16)-((11x-31))=0

We get rid of parentheses

6x+4x-((11x-31))-16=0



We calculate terms in parentheses: -((11x-31)), so:

(11x-31)

We get rid of parentheses

11x-31

Back to the equation:

-(11x-31)



We add all the numbers together, and all the variables

10x-(11x-31)-16=0

We get rid of parentheses

10x-11x+31-16=0

We add all the numbers together, and all the variables

-1x+15=0

We move all terms containing x to the left, all other terms to the right

-x=-15

x=-15/-1

x=+15

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