(4x-16/x-5)(3x-15/8x-32)

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Solution for (4x-16/x-5)(3x-15/8x-32) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4*x-(16/x)-5)*(3*x-((15/8)*x)-32) = 0

(4*x-16*x^-1-5)*(3*x+(-15/8)*x-32) = 0

(4*x-16*x^-1-5)*(9/8*x-32) = 0

4*x-16*x^-1-5 = 0

4*x^1-16*x^-1-5*x^0 = 0

(4*x^2-5*x^1-16*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-5*x^1-16*x^0) = 0

x^1

4*x^2-5*x-16 = 0

4*x^2-5*x-16 = 0

DELTA = (-5)^2-(-16*4*4)

DELTA = 281

DELTA > 0

x = (281^(1/2)+5)/(2*4) or x = (5-281^(1/2))/(2*4)

x = (281^(1/2)+5)/8 or x = (5-281^(1/2))/8

x in { (5-281^(1/2))/8, (281^(1/2)+5)/8}

(x-((5-281^(1/2))/8))*(x-((281^(1/2)+5)/8)) = 0

(x-((5-281^(1/2))/8))*(x-((281^(1/2)+5)/8))*(9/8*x-32) = 0

( 9/8*x-32 )

9/8*x-32 = 0 // + 32

9/8*x = 32 // : 9/8

x = 32/9/8

x = 256/9

( x-((281^(1/2)+5)/8) )

x-((281^(1/2)+5)/8) = 0 // + (281^(1/2)+5)/8

x = (281^(1/2)+5)/8

( x-((5-281^(1/2))/8) )

x-((5-281^(1/2))/8) = 0 // + (5-281^(1/2))/8

x = (5-281^(1/2))/8

x in { 256/9, (281^(1/2)+5)/8, (5-281^(1/2))/8 }

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