(4x-18)(3x)=360

Solution for (4x-18)(3x)=360 equation:

(4x-18)(3x)=360

We move all terms to the left:

(4x-18)(3x)-(360)=0

We multiply parentheses

12x^2-54x-360=0

a = 12; b = -54; c = -360;
Δ = b2-4ac
Δ = -542-4·12·(-360)
Δ = 20196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20196}=\sqrt{36*561}=\sqrt{36}*\sqrt{561}=6\sqrt{561}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-6\sqrt{561}}{2*12}=\frac{54-6\sqrt{561}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+6\sqrt{561}}{2*12}=\frac{54+6\sqrt{561}}{24}
$