(4x-18)+(3x-8)=190

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Solution for (4x-18)+(3x-8)=190 equation: 



(4x-18)+(3x-8)=190

We move all terms to the left:

(4x-18)+(3x-8)-(190)=0

We get rid of parentheses

4x+3x-18-8-190=0

We add all the numbers together, and all the variables

7x-216=0

We move all terms containing x to the left, all other terms to the right

7x=216

x=216/7

x=30+6/7

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