(4x-18)+(8x-6)=(9x+15)

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Solution for (4x-18)+(8x-6)=(9x+15) equation: 



(4x-18)+(8x-6)=(9x+15)

We move all terms to the left:

(4x-18)+(8x-6)-((9x+15))=0

We get rid of parentheses

4x+8x-((9x+15))-18-6=0



We calculate terms in parentheses: -((9x+15)), so:

(9x+15)

We get rid of parentheses

9x+15

Back to the equation:

-(9x+15)



We add all the numbers together, and all the variables

12x-(9x+15)-24=0

We get rid of parentheses

12x-9x-15-24=0

We add all the numbers together, and all the variables

3x-39=0

We move all terms containing x to the left, all other terms to the right

3x=39

x=39/3

x=13

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