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(4x-19)(2x+17)=0
We multiply parentheses ..
(+8x^2+68x-38x-323)=0
We get rid of parentheses
8x^2+68x-38x-323=0
We add all the numbers together, and all the variables
8x^2+30x-323=0
a = 8; b = 30; c = -323;
Δ = b2-4ac
Δ = 302-4·8·(-323)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11236}=106$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-106}{2*8}=\frac{-136}{16} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+106}{2*8}=\frac{76}{16} =4+3/4 $
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