(4x-19)=(3x+16)

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Solution for (4x-19)=(3x+16) equation: 



(4x-19)=(3x+16)

We move all terms to the left:

(4x-19)-((3x+16))=0

We get rid of parentheses

4x-((3x+16))-19=0



We calculate terms in parentheses: -((3x+16)), so:

(3x+16)

We get rid of parentheses

3x+16

Back to the equation:

-(3x+16)



We get rid of parentheses

4x-3x-16-19=0

We add all the numbers together, and all the variables

x-35=0

We move all terms containing x to the left, all other terms to the right

x=35

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