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(4x-2)(11x+17)=90
We move all terms to the left:
(4x-2)(11x+17)-(90)=0
We multiply parentheses ..
(+44x^2+68x-22x-34)-90=0
We get rid of parentheses
44x^2+68x-22x-34-90=0
We add all the numbers together, and all the variables
44x^2+46x-124=0
a = 44; b = 46; c = -124;
Δ = b2-4ac
Δ = 462-4·44·(-124)
Δ = 23940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23940}=\sqrt{36*665}=\sqrt{36}*\sqrt{665}=6\sqrt{665}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-6\sqrt{665}}{2*44}=\frac{-46-6\sqrt{665}}{88} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+6\sqrt{665}}{2*44}=\frac{-46+6\sqrt{665}}{88} $
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