(4x-2)(2-x)=0

Solution for (4x-2)(2-x)=0 equation:

(4x-2)(2-x)=0

We add all the numbers together, and all the variables

(4x-2)(-1x+2)=0

We multiply parentheses ..

(-4x^2+8x+2x-4)=0

We get rid of parentheses

-4x^2+8x+2x-4=0

We add all the numbers together, and all the variables

-4x^2+10x-4=0

a = -4; b = 10; c = -4;
Δ = b2-4ac
Δ = 102-4·(-4)·(-4)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-6}{2*-4}=\frac{-16}{-8}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+6}{2*-4}=\frac{-4}{-8}
=1/2
$