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(4x-2)(2x-4)=0
We multiply parentheses ..
(+8x^2-16x-4x+8)=0
We get rid of parentheses
8x^2-16x-4x+8=0
We add all the numbers together, and all the variables
8x^2-20x+8=0
a = 8; b = -20; c = +8;
Δ = b2-4ac
Δ = -202-4·8·8
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-12}{2*8}=\frac{8}{16} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+12}{2*8}=\frac{32}{16} =2 $
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