(4x-2)(4x+2)=300

Solution for (4x-2)(4x+2)=300 equation:

(4x-2)(4x+2)=300

We move all terms to the left:

(4x-2)(4x+2)-(300)=0

We use the square of the difference formula

16x^2-4-300=0

We add all the numbers together, and all the variables

16x^2-304=0

a = 16; b = 0; c = -304;
Δ = b2-4ac
Δ = 02-4·16·(-304)
Δ = 19456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19456}=\sqrt{1024*19}=\sqrt{1024}*\sqrt{19}=32\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{19}}{2*16}=\frac{0-32\sqrt{19}}{32}
=-\frac{32\sqrt{19}}{32}
=-\sqrt{19}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{19}}{2*16}=\frac{0+32\sqrt{19}}{32}
=\frac{32\sqrt{19}}{32}
=\sqrt{19}
$