(4x-2)+(2x+28)=x

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Solution for (4x-2)+(2x+28)=x equation: 



(4x-2)+(2x+28)=x

We move all terms to the left:

(4x-2)+(2x+28)-(x)=0

We add all the numbers together, and all the variables

-1x+(4x-2)+(2x+28)=0

We get rid of parentheses

-1x+4x+2x-2+28=0

We add all the numbers together, and all the variables

5x+26=0

We move all terms containing x to the left, all other terms to the right

5x=-26

x=-26/5

x=-5+1/5

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