(4x-2)+(3x+2)+103=180

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Solution for (4x-2)+(3x+2)+103=180 equation: 



(4x-2)+(3x+2)+103=180

We move all terms to the left:

(4x-2)+(3x+2)+103-(180)=0

We add all the numbers together, and all the variables

(4x-2)+(3x+2)-77=0

We get rid of parentheses

4x+3x-2+2-77=0

We add all the numbers together, and all the variables

7x-77=0

We move all terms containing x to the left, all other terms to the right

7x=77

x=77/7

x=11

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