(4x-2)+(3x+6)+(x)=180

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Solution for (4x-2)+(3x+6)+(x)=180 equation: 



(4x-2)+(3x+6)+(x)=180

We move all terms to the left:

(4x-2)+(3x+6)+(x)-(180)=0

We add all the numbers together, and all the variables

x+(4x-2)+(3x+6)-180=0

We get rid of parentheses

x+4x+3x-2+6-180=0

We add all the numbers together, and all the variables

8x-176=0

We move all terms containing x to the left, all other terms to the right

8x=176

x=176/8

x=22

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