(4x-2)+(3x+7)+(4x-2)+(3x+7)=

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Solution for (4x-2)+(3x+7)+(4x-2)+(3x+7)= equation:


(4x-2)+(3x+7)+(4x-2)+(3x+7)=0

We simplify the equation to the form, which is simple to understand 
(4x-2)+(3x+7)+(4x-2)+(3x+7)=0

Remove unnecessary parentheses
4x-2+(3x+7)+(4x-2)+(3x+7)=0

Remove unnecessary parentheses
+4x-2+3x+7+(+4x-2+)+(+3x+7+)=0

Remove unnecessary parentheses
+4x-2+3x+7+4x-2+(+3x+7+)=0

Remove unnecessary parentheses
+4x-2+3x+7+4x-2+3x+7=0

We move all terms containing x to the left and all other terms to the right. 
+4x+3x+4x+3x=0+2-7+2-7

We simplify left and right side of the equation. 
+14x=-10

We divide both sides of the equation by 14 to get x. 
x=-0.714285714286

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