(4x-2)+(6)=(7x-2)

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Solution for (4x-2)+(6)=(7x-2) equation: 



(4x-2)+(6)=(7x-2)

We move all terms to the left:

(4x-2)+(6)-((7x-2))=0

We get rid of parentheses

4x-((7x-2))-2+6=0



We calculate terms in parentheses: -((7x-2)), so:

(7x-2)

We get rid of parentheses

7x-2

Back to the equation:

-(7x-2)



We add all the numbers together, and all the variables

4x-(7x-2)+4=0

We get rid of parentheses

4x-7x+2+4=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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