(4x-2)+40+(9x+62)=180

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Solution for (4x-2)+40+(9x+62)=180 equation: 



(4x-2)+40+(9x+62)=180

We move all terms to the left:

(4x-2)+40+(9x+62)-(180)=0

We add all the numbers together, and all the variables

(4x-2)+(9x+62)-140=0

We get rid of parentheses

4x+9x-2+62-140=0

We add all the numbers together, and all the variables

13x-80=0

We move all terms containing x to the left, all other terms to the right

13x=80

x=80/13

x=6+2/13

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