(4x-2)-(6x+8)+2(4x-3)=16x+14

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Solution for (4x-2)-(6x+8)+2(4x-3)=16x+14 equation: 



(4x-2)-(6x+8)+2(4x-3)=16x+14

We move all terms to the left:

(4x-2)-(6x+8)+2(4x-3)-(16x+14)=0

We multiply parentheses

(4x-2)-(6x+8)+8x-(16x+14)-6=0

We get rid of parentheses

4x-6x+8x-16x-2-8-14-6=0

We add all the numbers together, and all the variables

-10x-30=0

We move all terms containing x to the left, all other terms to the right

-10x=30

x=30/-10

x=-3

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