(4x-2)/3=-(x-7)/2

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Solution for (4x-2)/3=-(x-7)/2 equation: 



(4x-2)/3=-(x-7)/2

We move all terms to the left:

(4x-2)/3-(-(x-7)/2)=0

We calculate fractions


4x/()+(-(-(x-7)*3)/()=0



We calculate terms in parentheses: +(-(-(x-7)*3)/(), so:

-(-(x-7)*3)/(

We multiply all the terms by the denominator


-(-(x-7)*3)



We calculate terms in parentheses: -(-(x-7)*3), so:

-(x-7)*3

We multiply parentheses

-3x+21

Back to the equation:

-(-3x+21)



We get rid of parentheses

3x-21

Back to the equation:

+(3x-21)



We get rid of parentheses

4x/()+3x-21=0

We multiply all the terms by the denominator


4x+3x*()-21*()=0

We add all the numbers together, and all the variables

4x+3x*()=0

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