(4x-2)=(2x+12)=(3x+8)

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Solution for (4x-2)=(2x+12)=(3x+8) equation: 



(4x-2)=(2x+12)=(3x+8)

We move all terms to the left:

(4x-2)-((2x+12))=0

We get rid of parentheses

4x-((2x+12))-2=0



We calculate terms in parentheses: -((2x+12)), so:

(2x+12)

We get rid of parentheses

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

4x-2x-12-2=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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