(4x-2)=-2(3+6x)-5

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Solution for (4x-2)=-2(3+6x)-5 equation: 



(4x-2)=-2(3+6x)-5

We move all terms to the left:

(4x-2)-(-2(3+6x)-5)=0

We add all the numbers together, and all the variables

(4x-2)-(-2(6x+3)-5)=0

We get rid of parentheses

4x-(-2(6x+3)-5)-2=0



We calculate terms in parentheses: -(-2(6x+3)-5), so:

-2(6x+3)-5

We multiply parentheses

-12x-6-5

We add all the numbers together, and all the variables

-12x-11

Back to the equation:

-(-12x-11)



We get rid of parentheses

4x+12x+11-2=0

We add all the numbers together, and all the variables

16x+9=0

We move all terms containing x to the left, all other terms to the right

16x=-9

x=-9/16

x=-9/16

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