(4x-20)+x=108

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Solution for (4x-20)+x=108 equation: 



(4x-20)+x=108

We move all terms to the left:

(4x-20)+x-(108)=0

We add all the numbers together, and all the variables

x+(4x-20)-108=0

We get rid of parentheses

x+4x-20-108=0

We add all the numbers together, and all the variables

5x-128=0

We move all terms containing x to the left, all other terms to the right

5x=128

x=128/5

x=25+3/5

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