(4x-22)+(10x-4)+(x-11)=180

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Solution for (4x-22)+(10x-4)+(x-11)=180 equation: 



(4x-22)+(10x-4)+(x-11)=180

We move all terms to the left:

(4x-22)+(10x-4)+(x-11)-(180)=0

We get rid of parentheses

4x+10x+x-22-4-11-180=0

We add all the numbers together, and all the variables

15x-217=0

We move all terms containing x to the left, all other terms to the right

15x=217

x=217/15

x=14+7/15

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