(4x-27)=(3x+12)

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Solution for (4x-27)=(3x+12) equation: 



(4x-27)=(3x+12)

We move all terms to the left:

(4x-27)-((3x+12))=0

We get rid of parentheses

4x-((3x+12))-27=0



We calculate terms in parentheses: -((3x+12)), so:

(3x+12)

We get rid of parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

4x-3x-12-27=0

We add all the numbers together, and all the variables

x-39=0

We move all terms containing x to the left, all other terms to the right

x=39

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