(4x-28)=(10x-2)=180

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Solution for (4x-28)=(10x-2)=180 equation: 



(4x-28)=(10x-2)=180

We move all terms to the left:

(4x-28)-((10x-2))=0

We get rid of parentheses

4x-((10x-2))-28=0



We calculate terms in parentheses: -((10x-2)), so:

(10x-2)

We get rid of parentheses

10x-2

Back to the equation:

-(10x-2)



We get rid of parentheses

4x-10x+2-28=0

We add all the numbers together, and all the variables

-6x-26=0

We move all terms containing x to the left, all other terms to the right

-6x=26

x=26/-6

x=-4+1/3

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