(4x-28)=(3x+13)

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Solution for (4x-28)=(3x+13) equation: 



(4x-28)=(3x+13)

We move all terms to the left:

(4x-28)-((3x+13))=0

We get rid of parentheses

4x-((3x+13))-28=0



We calculate terms in parentheses: -((3x+13)), so:

(3x+13)

We get rid of parentheses

3x+13

Back to the equation:

-(3x+13)



We get rid of parentheses

4x-3x-13-28=0

We add all the numbers together, and all the variables

x-41=0

We move all terms containing x to the left, all other terms to the right

x=41

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