(4x-28)=(3x+16)

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Solution for (4x-28)=(3x+16) equation:



(4x-28)=(3x+16)
We move all terms to the left:
(4x-28)-((3x+16))=0
We get rid of parentheses
4x-((3x+16))-28=0
We calculate terms in parentheses: -((3x+16)), so:
(3x+16)
We get rid of parentheses
3x+16
Back to the equation:
-(3x+16)
We get rid of parentheses
4x-3x-16-28=0
We add all the numbers together, and all the variables
x-44=0
We move all terms containing x to the left, all other terms to the right
x=44

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