(4x-28)=(x+68)

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Solution for (4x-28)=(x+68) equation: 



(4x-28)=(x+68)

We move all terms to the left:

(4x-28)-((x+68))=0

We get rid of parentheses

4x-((x+68))-28=0



We calculate terms in parentheses: -((x+68)), so:

(x+68)

We get rid of parentheses

x+68

Back to the equation:

-(x+68)



We get rid of parentheses

4x-x-68-28=0

We add all the numbers together, and all the variables

3x-96=0

We move all terms containing x to the left, all other terms to the right

3x=96

x=96/3

x=32

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