(4x-2=16,x)

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Solution for (4x-2=16,x) equation: 



(4x-2=16.x)

We move all terms to the left:

(4x-2-(16.x))=0

We add all the numbers together, and all the variables

(4x-2-(+16.x))=0



We calculate terms in parentheses: +(4x-2-(+16.x)), so:

4x-2-(+16.x)

determiningTheFunctionDomain
4x-(+16.x)-2

We get rid of parentheses

4x-16.x-2

We add all the numbers together, and all the variables

-12x-2

Back to the equation:

+(-12x-2)



We get rid of parentheses

-12x-2=0

We move all terms containing x to the left, all other terms to the right

-12x=2

x=2/-12

x=-1/6

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