(4x-3)(2x+1)=4(x-3)(2x-5)

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Solution for (4x-3)(2x+1)=4(x-3)(2x-5) equation: 



(4x-3)(2x+1)=4(x-3)(2x-5)

We move all terms to the left:

(4x-3)(2x+1)-(4(x-3)(2x-5))=0

We multiply parentheses ..

(+8x^2+4x-6x-3)-(4(x-3)(2x-5))=0



We calculate terms in parentheses: -(4(x-3)(2x-5)), so:

4(x-3)(2x-5)

We multiply parentheses ..

4(+2x^2-5x-6x+15)

We multiply parentheses

8x^2-20x-24x+60

We add all the numbers together, and all the variables

8x^2-44x+60

Back to the equation:

-(8x^2-44x+60)



We get rid of parentheses

8x^2-8x^2+4x-6x+44x-3-60=0

We add all the numbers together, and all the variables

42x-63=0

We move all terms containing x to the left, all other terms to the right

42x=63

x=63/42

x=1+1/2

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