(4x-3)(3x+2)-2=(6x-7)(2x-5)

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Solution for (4x-3)(3x+2)-2=(6x-7)(2x-5) equation: 



(4x-3)(3x+2)-2=(6x-7)(2x-5)

We move all terms to the left:

(4x-3)(3x+2)-2-((6x-7)(2x-5))=0

We multiply parentheses ..

(+12x^2+8x-9x-6)-((6x-7)(2x-5))-2=0



We calculate terms in parentheses: -((6x-7)(2x-5)), so:

(6x-7)(2x-5)

We multiply parentheses ..

(+12x^2-30x-14x+35)

We get rid of parentheses

12x^2-30x-14x+35

We add all the numbers together, and all the variables

12x^2-44x+35

Back to the equation:

-(12x^2-44x+35)



We get rid of parentheses

12x^2-12x^2+8x-9x+44x-6-35-2=0

We add all the numbers together, and all the variables

43x-43=0

We move all terms containing x to the left, all other terms to the right

43x=43

x=43/43

x=1

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