(4x-3)(3x+2)=(2x-1)(6x-4)

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Solution for (4x-3)(3x+2)=(2x-1)(6x-4) equation: 



(4x-3)(3x+2)=(2x-1)(6x-4)

We move all terms to the left:

(4x-3)(3x+2)-((2x-1)(6x-4))=0

We multiply parentheses ..

(+12x^2+8x-9x-6)-((2x-1)(6x-4))=0



We calculate terms in parentheses: -((2x-1)(6x-4)), so:

(2x-1)(6x-4)

We multiply parentheses ..

(+12x^2-8x-6x+4)

We get rid of parentheses

12x^2-8x-6x+4

We add all the numbers together, and all the variables

12x^2-14x+4

Back to the equation:

-(12x^2-14x+4)



We get rid of parentheses

12x^2-12x^2+8x-9x+14x-6-4=0

We add all the numbers together, and all the variables

13x-10=0

We move all terms containing x to the left, all other terms to the right

13x=10

x=10/13

x=10/13

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